Question

the table gives the distribution of votes for a new school lunch option and grade level for 90 students.

lunch options	sixth	seventh	eighth	total
tacos	8	4	8	20
salad	4	6	6	16
sandwich	6	8	10	24
total	24	24	32	80

if one of these students is selected at random, what is the probability that the student voted for tacos?
a. $\frac{1}{6}$
b. $\frac{1}{5}$
c. $\frac{1}{4}$
d. $\frac{1}{3}$
e. $\frac{1}{2}$

Explanation:

Step1: Identify total students and Taco voters

Total students = 80 (from table's Total row).
Number of students who voted for Tacos = 20 (from Tacos row, Total column).

Step2: Calculate probability

Probability = $\frac{\text{Number of Taco voters}}{\text{Total students}}$ = $\frac{20}{80}$ = $\frac{1}{4}$? Wait, no—wait, the table says total students are 80? Wait, the problem statement says 90 students, but the table's total is 80. Wait, maybe a typo, but follow the table. Wait, Tacos total is 20, total students 80? Wait, no, let's check again. Wait, the table: Pizza total 20, Tacos 20, Salad 16, Sandwich 24. 20+20+16+24=80. So total students 80. So probability is 20/80 = 1/4? But wait, the options: C is 1/4. Wait, but let's recalculate. Wait, 20 divided by 80 is 1/4. Yes.

Answer:

C. $\frac{1}{4}$