Question

the table represents the results of a class survey. what is the relative frequency that someone will have chores, given that they have a sibling?
a 0.21
b 0.44
c 0.47
d 0.53
(table:

	have a sibling	only child
do not have chores	8	6	)

Explanation:

Step1: Identify relevant data

We need the number of people with a sibling and chores, and the total number of people with a sibling. From the table, number with sibling and chores is 7, number with sibling and no chores is 8. So total with sibling is \(7 + 8=15\).

Step2: Calculate relative frequency

Relative frequency is (number with sibling and chores) / (total with sibling) = \(\frac{7}{15}\approx0.47\)? Wait, no, wait: \(7\div15\approx0.466\approx0.47\)? Wait, no, wait, let's recalculate. Wait, 7 divided by (7 + 8) = 7/15 ≈ 0.466..., which is approximately 0.47? Wait, but let's check the options. Option C is 0.47, B is 0.44, D is 0.53. Wait, 7 divided by 15: 15*0.47 = 7.05, close to 7. Alternatively, maybe I misread the table. Wait, the table: "Have Chores" row, "Have a Sibling" column is 7; "Do Not Have Chores" row, "Have a Sibling" column is 8. So total with sibling is 7 + 8 = 15. So the relative frequency is 7/15 ≈ 0.466..., which rounds to 0.47, so option C. Wait, but let me check again. Wait, maybe the table is: Have Chores: Have a Sibling 7, Only Child 9; Do Not Have Chores: Have a Sibling 8, Only Child 6. So for the conditional probability P(Have Chores | Have a Sibling) = P(Have Chores and Have a Sibling) / P(Have a Sibling) = 7 / (7 + 8) = 7/15 ≈ 0.466..., which is approximately 0.47, so option C.

Answer:

C. 0.47