Question

the table shows the number of coins in a change dish. if malcolm selects two coins at random without replacement, what is the probability that he selects a nickel followed by a dime? express your answer as a decimal rounded to the nearest thousandth if necessary.

coin	number
nickel	6
dime	8
quarter	7

Explanation:

Step1: Calculate total number of coins

$8 + 6+8 + 7=29$

Step2: Calculate probability of selecting a nickel first

The number of nickels is 6. So the probability of selecting a nickel first is $\frac{6}{29}$.

Step3: Calculate probability of selecting a dime second

After selecting a nickel, there are $29 - 1=28$ coins left. The number of dimes is 8. So the probability of selecting a dime second is $\frac{8}{28}$.

Step4: Calculate the combined probability

The probability of selecting a nickel followed by a dime is $\frac{6}{29}\times\frac{8}{28}=\frac{48}{812}\approx0.059$

Answer:

$0.059$