QUESTION IMAGE
Question
the table shows y, the number of tons of waste left in a landfill after x months of waste relocation.
x | 0 | 6 | 12
y | 24 | 20 | 16
part a: which equation represents the data in the table?
$y = -\frac{2}{3}x + 24$
part b:
the slope represents a rate of \boxed{} ton(s) per month.
the y - intercept represents an initial amount of \boxed{} ton(s).
\
Part A
Step1: Recall slope - intercept form
The slope - intercept form of a linear equation is $y = mx + b$, where $m$ is the slope and $b$ is the $y$-intercept.
We can calculate the slope $m$ using the formula $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let's take two points from the table, say $(x_1,y_1)=(0,24)$ and $(x_2,y_2)=(6,20)$.
Step2: Calculate the slope
Using the slope formula $m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{20 - 24}{6 - 0}=\frac{- 4}{6}=-\frac{2}{3}$.
The $y$-intercept $b$ is the value of $y$ when $x = 0$. From the table, when $x = 0$, $y = 24$, so $b = 24$.
So the equation of the line is $y=-\frac{2}{3}x + 24$, which matches the given equation.
Step1: Recall the meaning of slope in a linear equation
In the linear equation $y=mx + b$, the slope $m$ represents the rate of change of $y$ with respect to $x$. From the equation $y = -\frac{2}{3}x+24$, the slope $m=-\frac{2}{3}$. This means that for each unit increase in $x$ (each month), $y$ (the number of tons of waste) changes by $-\frac{2}{3}$ tons. The negative sign indicates a decrease.
Step2: Determine the rate
So the slope represents a rate of $-\frac{2}{3}$ ton(s) per month.
Step1: Recall the meaning of y - intercept in a linear equation
In the linear equation $y=mx + b$, the $y$-intercept $b$ is the value of $y$ when $x = 0$. In the context of the problem, $x = 0$ represents the initial time (0 months of waste relocation).
Step2: Find the y - intercept from the equation or table
From the equation $y=-\frac{2}{3}x + 24$, when $x = 0$, $y=24$. Also, from the table, when $x = 0$, $y = 24$. So the $y$-intercept represents an initial amount of 24 tons.
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$y = -\frac{2}{3}x+24$