Question

it takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula. n₂ + 3h₂ → 2nh₃. identify which combination of molecules will produce ammonia with no leftovers? (1 point) o 4n₂ and 4h₂ o 2n₂ and 6h₂ o 8n₂ and 4h₂ o 5n₂ and 9h₂

Explanation:

Step1: Analyze reaction ratio

The balanced - chemical equation is $N_2 + 3H_2
ightarrow2NH_3$, which means 1 molecule of $N_2$ reacts with 3 molecules of $H_2$ to produce 2 molecules of $NH_3$ without any leftovers.

Step2: Check each option

For option A ($4N_2$ and $4H_2$), $H_2$ is the limiting reactant. 4 molecules of $H_2$ will react with $\frac{4}{3}$ molecules of $N_2$, and there will be leftover $N_2$.
For option B ($2N_2$ and $6H_2$), the ratio of $N_2$ to $H_2$ is $2:6 = 1:3$. According to the reaction equation, 2 molecules of $N_2$ will react with 6 molecules of $H_2$ exactly to produce 4 molecules of $NH_3$ with no leftovers.
For option C ($8N_2$ and $4H_2$), $H_2$ is the limiting reactant. 4 molecules of $H_2$ will react with $\frac{4}{3}$ molecules of $N_2$, and there will be a large amount of leftover $N_2$.
For option D ($5N_2$ and $9H_2$), $H_2$ is the limiting reactant. 9 molecules of $H_2$ will react with 3 molecules of $N_2$, and there will be 2 leftover $N_2$ molecules.

Answer:

B. $2N_2$ and $6H_2$