Question

term to the correct location on the expression. each term can be used more than once, but not a completely factored form of the quadratic expression $3x^2 - 30x - 72$? $x$ $4$ $x^2$ $1$ $3$ $6$ $12$ $3x$ $square(x - square)(square + 2)$ reset next

Explanation:

Step1: Factor out GCF

First, factor out the greatest common factor (GCF) from $3x^2 - 30x - 72$. The GCF of 3, -30, and -72 is 3.
$3x^2 - 30x - 72 = 3(x^2 - 10x - 24)$

Step2: Factor quadratic trinomial

Factor the quadratic $x^2 - 10x - 24$. We need two numbers that multiply to -24 and add to -10. These numbers are -12 and 2.
$x^2 - 10x - 24 = (x - 12)(x + 2)$

Step3: Combine factors

Substitute the factored quadratic back into the expression from Step1.
$3(x^2 - 10x - 24) = 3(x - 12)(x + 2)$

Answer:

$3(x - 12)(x + 2)$
(The terms to fill in the blanks are: 3, 12, $x$)