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tewkesbury housing authority analyzes the number of people per building…

Question

tewkesbury housing authority analyzes the number of people per building on every street. here is the data for prentiss court in 2023, which has only single - family homes. each circle shows the number of people in one building. the mean number of people is 2.2 and the median number of people is 2.3. mean 2.2 median: 2.3 0 4 6 8 10 number of people in 2024, a new apartment building is built on prentiss court with 9 people a b c d 0 4 6 8 10 number of people question 1: which of the lines (a, b, c, or d) shown above is most likely to be the mean after including the new apartment building? a b c d question 2: which of the lines (a, b, c, or d) is most likely to be the median after including the new apartment building

Explanation:

Step1: Find original total people

Let original number of buildings = $n$. Mean = $\frac{\text{Total people}}{n}=2.2$, so total people = $2.2n$.

Step2: Find new total and count

New total people = $2.2n + 9$, new count = $n+1$.

Step3: Calculate new mean

New mean = $\frac{2.2n + 9}{n+1} = \frac{2.2(n+1) + 9 - 2.2}{n+1} = 2.2 + \frac{6.8}{n+1}$.
From median=2.3, $n$ is odd, original data has most values at 2. Count $n$: median is $\frac{n+1}{2}$th value=2.3? No, median is 2.3, so $n=10$ (since median of 10 data: average of 5th and 6th, (2+2.6)/2=2.3? No, simpler: original mean 2.2, if $n=10$, total=22. New total=22+9=31, new mean=$\frac{31}{11}\approx2.82$, which is close to line B.

Step4: Find new median

Original $n$: median=2.3, so $n$ is even: average of $\frac{n}{2}$th and $(\frac{n}{2}+1)$th values=2.3. So one is 2, one is 2.6. When adding 9 (largest value), new count $n+1$ (odd). Median is $(\frac{n+1+1}{2})=(\frac{n}{2}+1)$th value, which is 2.3? No, original data: most values are 2, adding 9 shifts median to the next value, which is still ~2, close to line A.

Answer:

Question 1: B
Question 2: A