Question

there is 1 red gumdrop and 4 green gumdrops in a small jar. also, 2 pieces of butterscotch candy and 3 pieces of cinnamon candy are in another jar. if craig draws one piece of candy from each jar without looking, whats the probability that he will get a red gumdrop and a piece of butterscotch candy? a. \\(\frac{2}{25}\\) b. \\(\frac{3}{10}\\) c. \\(\frac{4}{25}\\) d. \\(\frac{3}{25}\\)

Explanation:

Step1: Calculate total gumdrops

Total gumdrops = 1 red + 4 green = 5

Step2: Probability of red gumdrop

Probability (red gumdrop) = $\frac{\text{Number of red gumdrops}}{\text{Total gumdrops}} = \frac{1}{5}$

Step3: Calculate total candies

Total candies = 2 butterscotch + 3 cinnamon = 5

Step4: Probability of butterscotch candy

Probability (butterscotch) = $\frac{\text{Number of butterscotch}}{\text{Total candies}} = \frac{2}{5}$

Step5: Multiply independent probabilities

Combined probability = $\frac{1}{5} \times \frac{2}{5} = \frac{2}{25}$

Answer:

A. $\frac{2}{25}$