Question

these models show two different waves eli created in the spring toy.
wave 1
wave 2
assuming the waves are traveling at the same speed, compare the waves.

greater for wave 1

greater for wave 2

equal for both waves

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the amplitude is

○

○

○

the wavelength is

○

○

○

the frequency is

○

○

○

Explanation:

Step1: Analyze wave amplitude

Amplitude is the maximum displacement from the rest position. Looking at both waves, the outward loops (displacement) are the same size for Wave 1 and Wave 2.

Step2: Analyze wave wavelength

Wavelength is the distance between identical points on consecutive waves. Wave 1 has fewer compressed sections per unit length, so its wavelength is longer. Wave 2 has more compressed sections, meaning shorter wavelength. Thus, wavelength is greater for Wave 1.

Step3: Relate speed, wavelength, frequency

Use the wave speed formula $v = f\lambda$, rearranged to $f = \frac{v}{\lambda}$. Since $v$ is equal for both waves, frequency is inversely proportional to wavelength. Wave 2 has a shorter wavelength, so its frequency is greater.

Answer:

	greater for Wave 1	greater for Wave 2	equal for both waves
The wavelength is	$\boldsymbol{\bigcirc}$
The frequency is		$\boldsymbol{\bigcirc}$