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9 - 3 ÷ (1/3) + 1 =? 6 ÷ 2(1+2) =
here is a math problem for you: what is the value of 3 + 3 × 3 - 3 + 3?
using the order of operations (pemdas/bodmas) you must perform multiplication
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Explanation:

Step1: Solve $9-3\div\frac{1}{3}+1$

First handle division: $3\div\frac{1}{3}=3\times3=9$
Now compute the rest: $9-9+1=1$

Step2: Solve $6\div2(1+2)$

First calculate parentheses: $1+2=3$
Then do division/multiplication left to right: $6\div2\times3=3\times3=9$

Step3: Solve $3+3\times3-3+3$

First handle multiplication: $3\times3=9$
Now compute the rest: $3+9-3+3=12$

Answer:

$9-3\div\frac{1}{3}+1 = 1$
$6\div2(1+2) = 9$
$3+3\times3-3+3 = 12$