Question

1. through: (-3, -1) and (4, -1)

Explanation:

Assuming the problem is to find the equation of the line through the points \((-3, -1)\) and \((4, -1)\).

Step 1: Find the slope

The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Here, \(x_1=-3,y_1 = - 1,x_2 = 4,y_2=-1\). So \(m=\frac{-1-(-1)}{4 - (-3)}=\frac{-1 + 1}{4 + 3}=\frac{0}{7}=0\).

Step 2: Use point - slope form

The point - slope form of a line is \(y - y_1=m(x - x_1)\). We can use the point \((-3,-1)\) (we could also use \((4,-1)\)). Substituting \(m = 0\), \(x_1=-3\) and \(y_1=-1\) into the formula: \(y-(-1)=0\times(x - (-3))\). Simplifying, we get \(y + 1=0\), so \(y=-1\).

Answer:

The equation of the line is \(y=-1\)