QUESTION IMAGE
Question
time spent by children
| at least 1 hr/day using electronics | less than 1 hr/day using electronics | total | |
|---|---|---|---|
| less than 1 hr/day outside | 42 | 6 | 48 |
| total | 44 | 20 | 64 |
given that a child spends at least 1 hour per day outside, what is the probability, rounded to the nearest hundredth if necessary, that the child spends less than 1 hour per day on electronics?
0.22
0.25
0.70
0.88
Step1: Identify relevant values
We want the probability that a child spends less than 1 - hour per day on electronics given they spend at least 1 hour per day outside. The number of children who spend at least 1 hour per day outside and less than 1 hour per day on electronics is 14, and the total number of children who spend at least 1 hour per day outside is 16.
Step2: Calculate probability
The formula for conditional - probability in this case is $P(A|B)=\frac{n(A\cap B)}{n(B)}$, where $A$ is the event of spending less than 1 hour per day on electronics and $B$ is the event of spending at least 1 hour per day outside. So the probability $P=\frac{14}{16}=\frac{7}{8} = 0.875\approx0.88$.
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0.88