Question

the titration of vitamin c with iodine proceeds according to the given equation. c₆h₈o₆ + i₂ → c₆h₆o₆ + 2hi. suppose it takes 14.92 ml of 0.0053 m i₂ solution to reach the end - point of the titration. how many moles of i₂ reacted? type answer:

Explanation:

Step1: Convert volume to liters

We know that $1\ L = 1000\ mL$. So, $V = 14.92\ mL=14.92\times10^{- 3}\ L$.

Step2: Use the molarity - moles formula

The formula for molarity $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles and $V$ is volume in liters. Rearranging for $n$, we get $n = M\times V$. Given $M = 0.0053\ M$ and $V=14.92\times 10^{-3}\ L$. Then $n=0.0053\ mol/L\times14.92\times 10^{-3}\ L$.
$n = 0.0053\times14.92\times10^{-3}\ mol=7.9076\times10^{-5}\ mol$.

Answer:

$7.91\times 10^{-5}\ mol$