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topic: perimeter and area progress: the movement of the progress bar ma…

Question

topic: perimeter and area
progress:
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer.
find the perimeter and the area of the polygon shape shown. all measurements are in inches.
perimeter = 24 inches, area = 44 square inches
perimeter = 32 inches, area = 20 square inches
perimeter = 24 inches, area = 20 square inches
perimeter = 32 inches, area = 44 square inches

Explanation:

Step1: Calculate the perimeter

Count the number of outer - side lengths. Each side length is 2 inches. There are 16 outer - side lengths. So the perimeter $P=16\times2 = 32$ inches.

Step2: Calculate the area

Count the number of 1 - inch by 1 - inch squares. The polygon is composed of 5 squares with side - length 2 inches. The area of a square with side - length $s$ is $A_{square}=s^{2}$. Here $s = 2$ inches, and the number of such squares $n = 5$. So the area $A=5\times(2\times2)=20$ square inches.

Answer:

Perimeter = 32 inches, Area = 20 square inches