Question

topic: perimeter and area
progress:
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer.
find the perimeter and area of the polygon shown below.
p = 91 feet, a = 390 square feet
p = 76 feet, a = 330 square feet
p = 76 feet, a = 338 square feet
p = 58 feet, a = 338 square feet

Explanation:

Step1: Calculate the perimeter

Add up the lengths of all sides. The sides are 15 ft, 18 ft, 17 ft, and the fourth - side length is 18 + 6=24 ft. So, $P=15 + 18+17 + 24$=$76$ ft.

Step2: Calculate the area

The polygon can be split into a rectangle and a triangle. The rectangle has length 18 ft and width 15 ft, and its area $A_{rect}=18\times15 = 270$ square feet. The triangle has base 6 ft and height 15 ft, and its area $A_{tri}=\frac{1}{2}\times6\times15=45$ square feet. Then $A = A_{rect}+A_{tri}=270 + 60=330$ square feet.

Answer:

B. $P = 76$ feet, $A = 330$ square feet