Question

1 / 3 to translate quadrilateral abcd by 1 unit to the right and 4 units up, we basically translate quadrilateral abcds vertices and connect them.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 1 unit right and 4 units up, the new - point is $(x + 1,y+4)$.

Step2: Find new coordinates of point A

If point $A$ has coordinates $(-3,-5)$, then the new coordinates of $A$ are $(-3 + 1,-5 + 4)=(-2,-1)$.

Step3: Find new coordinates of point B

If point $B$ has coordinates $(2,-2)$, then the new coordinates of $B$ are $(2 + 1,-2 + 4)=(3,2)$.

Step4: Find new coordinates of point C

If point $C$ has coordinates $(6,2)$, then the new coordinates of $C$ are $(6 + 1,2 + 4)=(7,6)$.

Step5: Find new coordinates of point D

If point $D$ has coordinates $(6,-1)$, then the new coordinates of $D$ are $(6 + 1,-1 + 4)=(7,3)$.

Step6: Connect the new - vertices

Connect the new vertices $A'(-2,-1)$, $B'(3,2)$, $C'(7,6)$ and $D'(7,3)$ to form the translated quadrilateral.

Answer:

The new coordinates of the vertices of the translated quadrilateral are $A'(-2,-1)$, $B'(3,2)$, $C'(7,6)$ and $D'(7,3)$.