QUESTION IMAGE
Question
translation: (x, y) → (x + 10, y + 6) and scale factor (enlargement ratio): 4; translation: (x, y) → (x - 10, y + 6) and scale factor (reduction ratio): 1/4; translation: (x, y) → (x + 10, y - 6) and scale factor (enlargement ratio): 4; translation: (x, y) → (x - 10, y - 6) and scale factor (reduction ratio): 1/4
Step1: Find centers of circles
From the graph, center \( C_1 \) is at \((-8, -3)\) and \( C_2 \) is at \((2, 2)\).
Step2: Analyze translation
To go from \( C_1(-8, -3) \) to \( C_2(2, 2) \):
- Change in \( x \): \( 2 - (-8) = 10 \), so \( x \to x + 10 \).
- Change in \( y \): \( 2 - (-3) = 5 \)? Wait, no, wait the options have \( y + 6 \). Wait, maybe I misread. Wait, \( C_1 \) is small, \( C_2 \) is large. Wait, the first option: translation \( (x,y)\to(x + 10, y + 6) \), scale factor 4 (enlargement). Let's check distance. Radius of small circle: from \( C_1 \) to edge, say distance from \( C_1(-8,-3) \) to \( x=-6 \) (left edge) is 2, so radius 2. Large circle: from \( C_2(2,2) \) to \( x=-6 \) (left edge) is 8, so radius 8. Scale factor: \( 8/2 = 4 \) (enlargement). Translation: \( -8 + 10 = 2 \), \( -3 + 6 = 3 \)? Wait, \( C_2 \) is at (2,2). Wait, maybe \( y \) change: \( 2 - (-3) = 5 \), but option has \( y + 6 \). Wait, maybe my center for \( C_2 \) is (2,2)? Wait the graph: \( C_2 \) is at (2,2)? Wait the dot is at (2,2)? Wait the x-axis: 2, y-axis: 2. So \( C_2(2,2) \), \( C_1(-8,-3) \). Then \( x \): \( -8 + 10 = 2 \), \( y \): \( -3 + 6 = 3 \)? No, \( C_2 \) is at (2,2). Wait, maybe \( y \) is \( -3 + 5 = 2 \), but option has \( y + 6 \). Wait, maybe the small circle is \( C_1 \), large is \( C_2 \). Radius of small: let's see, from \( C_1(-8,-3) \) to \( x=-10 \) is 2, so radius 2. Large circle: from \( C_2(2,2) \) to \( x=-6 \) (left edge) is 8, so radius 8. Scale factor \( 8/2 = 4 \) (enlargement). Translation: \( x \): \( -8 + 10 = 2 \), \( y \): \( -3 + 6 = 3 \)? No, \( C_2 \) is at (2,2). Wait, maybe \( y \) is \( -3 + 5 = 2 \), but option has \( y + 6 \). Wait, maybe the center of \( C_2 \) is (2,2), and \( C_1 \) is (-8,-4)? No, the graph: \( C_1 \) is at (-8,-3), \( C_2 \) at (2,2). Then \( x \) translation: 10, \( y \) translation: 5, but option has \( y + 6 \). Wait, maybe the options: first option is translation \( (x,y)\to(x + 10, y + 6) \), scale factor 4. Let's check scale: small radius r, large radius 4r. So if small radius is 2, large is 8, which matches. Translation: \( x \): -8 + 10 = 2, \( y \): -3 + 6 = 3, but \( C_2 \) is at (2,2). Close, maybe typo, but the first option is the only one with enlargement (scale 4) and translation \( x + 10, y + 6 \).
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Translation: \((x, y) \to (x + 10, y + 6)\) and Scale factor (enlargement ratio): 4 (the first option)