Question

1. translation of trapezoid jklm, with vertices j(-6,6) k(-3,7) l(-1,3) m(-8,0)... (x,y)→(x + 7,y - 3) j( , ), k( , , l( , ), m( , )

Explanation:

Step1: Find new coordinates of J

For point J(-6, 6), use the translation rule $(x,y)\to(x + 7,y - 3)$.
$x=-6,y = 6$, then $x'=-6 + 7=1,y'=6-3 = 3$. So J'(1,3).

Step2: Find new coordinates of K

For point K(-3, 7), with $x=-3,y = 7$. Then $x'=-3 + 7=4,y'=7-3 = 4$. So K'(4,4).

Step3: Find new coordinates of L

For point L(-1, 3), with $x=-1,y = 3$. Then $x'=-1 + 7=6,y'=3-3 = 0$. So L'(6,0).

Step4: Find new coordinates of M

For point M(-8, 0), with $x=-8,y = 0$. Then $x'=-8 + 7=-1,y'=0-3=-3$. So M'(-1,-3).

Answer:

J'(1,3), K'(4,4), L'(6,0), M'(-1,-3)