Question

3.4 translations - graded
the vertices of a quadrilateral are:
a(-4, -2), b(-5, 3), c(6, 2), d(9, -1)
find the coordinates after the quadrilateral is translated up 2 units and left 1 unit.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated left $a$ units and up $b$ units, the new - point is $(x - a,y + b)$. Here $a = 1$ and $b = 2$.

Step2: Translate point A

For point $A(-4,-2)$, the new $x$ - coordinate is $x=-4 - 1=-5$ and the new $y$ - coordinate is $y=-2 + 2 = 0$. So $A'(-5,0)$.

Step3: Translate point B

For point $B(-5,3)$, the new $x$ - coordinate is $x=-5 - 1=-6$ and the new $y$ - coordinate is $y=3 + 2 = 5$. So $B'(-6,5)$.

Step4: Translate point C

For point $C(6,2)$, the new $x$ - coordinate is $x=6 - 1 = 5$ and the new $y$ - coordinate is $y=2+2 = 4$. So $C'(5,4)$.

Step5: Translate point D

For point $D(9,-1)$, the new $x$ - coordinate is $x=9 - 1 = 8$ and the new $y$ - coordinate is $y=-1 + 2 = 1$. So $D'(8,1)$.

Answer:

A'(-5,0)
B'(-6,5)
C'(5,4)
D'(8,1)