Question

trazar el gráfico de la recta.

y + 3x = -3

Explanation:

Step1: Rewrite the equation in slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept.
Starting with the equation $y+3x=-3$, we solve for $y$ by subtracting $3x$ from both sides:
$y=-3x - 3$

Step2: Find the y - intercept

The y - intercept occurs when $x = 0$. Substitute $x = 0$ into the equation $y=-3x - 3$:
$y=-3(0)-3=-3$
So, the y - intercept is the point $(0,-3)$.

Step3: Find the x - intercept

The x - intercept occurs when $y = 0$. Substitute $y = 0$ into the equation $y=-3x - 3$:
$0=-3x - 3$
Add $3x$ to both sides: $3x=-3$
Divide both sides by 3: $x = - 1$
So, the x - intercept is the point $(-1,0)$.

Step4: Plot the points and draw the line

Plot the points $(0,-3)$ (on the y - axis) and $(-1,0)$ (on the x - axis). Then, draw a straight line passing through these two points. This line represents the graph of the equation $y + 3x=-3$.

Answer:

To graph the line $y + 3x=-3$ (or $y=-3x - 3$), plot the points $(0,-3)$ (y - intercept) and $(-1,0)$ (x - intercept) and draw a straight line through them.