Question

triangle efd has vertices e(2,0), f(4,4), and d(5,-2). what are the vertices of the triangle after a rotation of 180° counterclockwise about the origin? first vertex: e(2,0). second vertex: f(4,4). third vertex: d(5,-2). therefore, all three vertices are:

Explanation:

Step1: Recall rotation rule

For a 180 - degree counter - clockwise rotation about the origin, the rule is $(x,y)\to(-x,-y)$.

Step2: Apply rule to point E

For point E(2,0), using the rule $(x,y)\to(-x,-y)$, we get $E'( - 2,0)$.

Step3: Apply rule to point F

For point F(4,4), using the rule $(x,y)\to(-x,-y)$, we get $F'( - 4,-4)$.

Step4: Apply rule to point D

For point D(5, - 2), using the rule $(x,y)\to(-x,-y)$, we get $D'( - 5,2)$.

Answer:

$E'(-2,0),F'(-4,-4),D'(-5,2)$