Question

triangle xyz has vertices x(-1, -3), y(0, 0), and z(1, -3). malik rotated the triangle 90° clockwise about the origin. what is the correct set of image points for triangle xyz?
○ x(3, -1), y(0, 0), z(3, 1)
○ x(1, 3), y(0, 0), z(-1, 3)
○ x(1, -3), y(0, 0), z(-1, -3)
○ x(-3, 1), y(0, 0), z(-3, -1)

Explanation:

Step1: Recall 90° clockwise rotation rule

For a point $(x,y)$, 90° clockwise about origin transforms to $(y, -x)$.

Step2: Apply rule to $X(-1,-3)$

Substitute $x=-1, y=-3$: $(-3, -(-1)) = (-3, 1)$

Step3: Apply rule to $Y(0,0)$

Substitute $x=0, y=0$: $(0, -0) = (0, 0)$

Step4: Apply rule to $Z(1,-3)$

Substitute $x=1, y=-3$: $(-3, -(1)) = (-3, -1)$

Answer:

$X'(-3, 1), Y'(0, 0), Z'(-3, -1)$