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triangles abc and abc are similar. identify the type of reflection perf…

Question

triangles abc and abc are similar. identify the type of reflection performed and the scale factor of dilation.
graph of coordinate plane with triangles abc and abc
options:

  • to obtain δabc, δabc is reflected across the y - axis and dilated with a scale factor of 2
  • to obtain δabc, δabc is reflected across the x - axis and dilated with a scale factor of 1/2
  • to obtain δabc, δabc is reflected across the x - axis and dilated with a scale factor of 2
  • to obtain δabc, δabc is reflected across the y - axis and dilated with a scale factor of 1/2

Explanation:

Step1: Identify Reflection Axis

First, observe the coordinates of the original triangle \( \triangle ABC \) and the transformed triangle \( \triangle A''B''C'' \). The original triangle is above the \( x \)-axis, and the transformed one is below, so the reflection is across the \( x \)-axis.

Step2: Calculate Scale Factor

Find the lengths of corresponding sides. For example, the length of \( BC \) in \( \triangle ABC \): \( B(-4,4) \), \( C(-2,4) \), so length \( BC = |-2 - (-4)| = 2 \). In \( \triangle A''B''C'' \), \( B''(-8,-8) \), \( C''(-2,-8) \), length \( B''C'' = |-2 - (-8)| = 6 \)? Wait, no, wait, let's check coordinates again. Wait, original \( A(-2,1) \), \( B(-4,4) \), \( C(-2,4) \). Transformed \( A''(-4,-2) \), \( B''(-8,-8) \), \( C''(-2,-8) \). Wait, distance between \( B \) and \( C \): \( x \)-coordinates: -4 to -2, so length 2. Distance between \( B'' \) and \( C'' \): -8 to -2, length 6? No, wait, maybe I messed up. Wait, original \( BC \) is horizontal from \( x=-4 \) to \( x=-2 \), so length 2 (since \( y \)-coordinate is 4 for both). Transformed \( B'' \) is at (-8, -8), \( C'' \) at (-2, -8), so horizontal distance is \( |-2 - (-8)| = 6 \)? No, that can't be. Wait, maybe original \( AB \): \( A(-2,1) \), \( B(-4,4) \). The distance is \( \sqrt{(-4 + 2)^2 + (4 - 1)^2} = \sqrt{4 + 9} = \sqrt{13} \). Transformed \( A''(-4,-2) \), \( B''(-8,-8) \). Distance \( A''B'' = \sqrt{(-8 + 4)^2 + (-8 + 2)^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13} \). So the scale factor is \( \frac{2\sqrt{13}}{\sqrt{13}} = 2 \). So the scale factor is 2.

Step3: Match with Options

From step1, reflection across \( x \)-axis, and scale factor 2. So the correct option is the one with reflection across \( x \)-axis and scale factor 2.

Answer:

To obtain \( \triangle A''B''C'' \), \( \triangle ABC \) is reflected across the \( x \)-axis and dilated with a scale factor of 2 (the third option).