Question

troy pushes on a car for 20 seconds, during which he applies an impulse of 3000 kg·m/s. what force does he apply to the car?
a. 150 n
b. 3000 n
c. 60,000 n
d. 0.0067 n

Explanation:

Step1: Recall impulse - force formula

Impulse $J = F\times\Delta t$, where $J$ is impulse, $F$ is force and $\Delta t$ is time interval. We need to solve for $F$.

Step2: Rearrange the formula for $F$

$F=\frac{J}{\Delta t}$

Step3: Substitute given values

Given $J = 3000\ kg\cdot m/s$ and $\Delta t=20\ s$. So $F=\frac{3000}{20}=150\ N$

Answer:

A. 150 N