Question

a truck has a mass of 1100 kg and experiences a friction of 400 n on a gravel surface. if the engine of the truck applies a force of 3000 n, what will the trucks acceleration be? a 2.36 m/s^2 b 3.09 m/s^2 c 2.20 m/s^2 d 2.72 m/s^2

Explanation:

Step1: Calculate net - force

The net - force $F_{net}$ is the difference between the force applied by the engine $F_{engine}$ and the frictional force $F_{friction}$. So, $F_{net}=F_{engine}-F_{friction}$. Given $F_{engine} = 3000\ N$ and $F_{friction}=400\ N$, then $F_{net}=3000 - 400=2600\ N$.

Step2: Use Newton's second law

Newton's second law is $F = ma$, where $F$ is the net - force, $m$ is the mass, and $a$ is the acceleration. We want to find $a$, and we know $m = 1100\ kg$ and $F = F_{net}=2600\ N$. Rearranging the formula for $a$ gives $a=\frac{F_{net}}{m}$. Substituting the values, we have $a=\frac{2600}{1100}\approx2.36\ m/s^{2}$.

Answer:

A. $2.36\ m/s^{2}$