Question

try again your answer is incorrect. find the area of the figure. (sides meet at right angles.)

Explanation:

Step1: Find area of large rectangle

The large rectangle has length $8$ cm and height $9$ cm. The area of a rectangle is $A = l\times h$. So the area of the large rectangle $A_1=8\times9 = 72$ $cm^2$.

Step2: Find area of small rectangle

The small rectangle has length $4$ cm and height $6$ cm. The area of the small rectangle $A_2 = 4\times6=24$ $cm^2$.

Step3: Find area of the figure

The area of the given figure $A$ is the area of the large rectangle minus the area of the small rectangle. So $A=A_1 - A_2=72- 24=48$ $cm^2$.

Answer:

$48$ $cm^2$