Question

a turbine engine produces 1857 hp at 109%, what is the 100% rating of this engine? (nearest whole number)
question 12 2 pts
an engine with a normal rating of 900 hp has an emergency rating of 980 hp, what percentage of the normal rating is the emergency rating? (nearest whole number)

Explanation:

Step1: Set up equation for first - question

Let the 100% rating be $x$. We know that $109\%$ of $x$ is 1857 hp. So, $1.09x = 1857$.

Step2: Solve for $x$

$x=\frac{1857}{1.09}\approx1704$.

Step3: Set up equation for second - question

Let the percentage be $p$. We know that $p\%$ of 900 hp is 980 hp. So, $\frac{p}{100}\times900 = 980$.

Step4: Solve for $p$

$9p = 980$, then $p=\frac{980}{9}\approx109$.

Answer:

1704
109