Question

two friends are both pregnant, and find out they are each expecting twins!

• let ( a ) be the event that one friend is pregnant with identical twins, and note that ( p(a) = 0.0045 ).
• let ( b ) be the event that the other friend is pregnant with fraternal twins, and note that ( p(b) = 0.01 ).

( a ) and ( b ) are independent events. what is the probability that one friend is pregnant with identical twins, and one friend is pregnant with fraternal twins?
give your answer as a percent, rounded to four decimal places if necessary and include the percent sign with your answer.
provide your answer below:

Explanation:

Step1: Recall the multiplication rule for independent events

For two independent events \( A \) and \( B \), the probability of both events occurring is given by \( P(A \cap B) = P(A) \times P(B) \).

Step2: Substitute the given probabilities

We know that \( P(A) = 0.0045 \) and \( P(B) = 0.01 \). So we calculate \( P(A) \times P(B) \):
\( 0.0045 \times 0.01 = 0.000045 \)

Step3: Convert to a percentage

To convert a decimal to a percentage, we multiply by 100. So \( 0.000045 \times 100 = 0.0045\% \)

Answer:

\( 0.0045\% \)