QUESTION IMAGE
Question
two parallel lines are crossed by a transversal. what is the value of x? (5x + 5)° 115° o x = 12 o x = 14 o x = 22 o x = 24
Step1: Use corresponding - angles property
Since the two parallel lines are crossed by a transversal, the angle \((5x + 5)^{\circ}\) and the \(115^{\circ}\) angle are corresponding angles and are equal. So we set up the equation \(5x+5 = 115\).
Step2: Solve the equation for \(x\)
Subtract 5 from both sides of the equation: \(5x+5 - 5=115 - 5\), which simplifies to \(5x=110\).
Step3: Isolate \(x\)
Divide both sides of the equation \(5x = 110\) by 5: \(\frac{5x}{5}=\frac{110}{5}\), so \(x = 22\).
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\(x = 22\)