QUESTION IMAGE
Question
tyler is building a pen for his rabbit on the side of the garage. he needs to fence in three sides and wants to use 24 ft of fencing.
- the table shows some possible lengths and widths. complete each area.
- which length and width combination should tyler choose to give his rabbit the most room?
| length (ft) | width (ft) | area (sq ft) |
|---|---|---|
| 10 | 7 | |
| 12 | 6 | |
| 14 | 5 | |
| 16 | 4 |
Part 1: Completing the Area Table
To find the area of a rectangle, we use the formula \( \text{Area} = \text{length} \times \text{width} \). Let's calculate the area for each row:
Row 1: Length = 8 ft, Width = 8 ft
Step 1: Apply the area formula
The formula for the area of a rectangle is \( A = l \times w \), where \( l \) is the length and \( w \) is the width.
Substitute \( l = 8 \) and \( w = 8 \) into the formula:
\( A = 8 \times 8 = 64 \) square feet.
Row 2: Length = 10 ft, Width = 7 ft
Step 1: Apply the area formula
Substitute \( l = 10 \) and \( w = 7 \) into \( A = l \times w \):
\( A = 10 \times 7 = 70 \) square feet.
Row 3: Length = 12 ft, Width = 6 ft
Step 1: Apply the area formula
Substitute \( l = 12 \) and \( w = 6 \) into \( A = l \times w \):
\( A = 12 \times 6 = 72 \) square feet.
Row 4: Length = 14 ft, Width = 5 ft
Step 1: Apply the area formula
Substitute \( l = 14 \) and \( w = 5 \) into \( A = l \times w \):
\( A = 14 \times 5 = 70 \) square feet.
Row 5: Length = 16 ft, Width = 4 ft
Step 1: Apply the area formula
Substitute \( l = 16 \) and \( w = 4 \) into \( A = l \times w \):
\( A = 16 \times 4 = 64 \) square feet.
The completed table is:
| length (ft) | width (ft) | area (sq ft) |
|---|---|---|
| 10 | 7 | 70 |
| 12 | 6 | 72 |
| 14 | 5 | 70 |
| 16 | 4 | 64 |
Part 2: Finding the Combination with the Most Room
To determine which length and width combination gives the most room (largest area), we compare the areas calculated in Part 1:
- For length = 8 ft, width = 8 ft: Area = 64 sq ft
- For length = 10 ft, width = 7 ft: Area = 70 sq ft
- For length = 12 ft, width = 6 ft: Area = 72 sq ft
- For length = 14 ft, width = 5 ft: Area = 70 sq ft
- For length = 16 ft, width = 4 ft: Area = 64 sq ft
Among these areas, 72 square feet is the largest, which corresponds to a length of 12 ft and a width of 6 ft.
Final Answers
Part 1:
| length (ft) | width (ft) | area (sq ft) |
|---|---|---|
| 10 | 7 | 70 |
| 12 | 6 | 72 |
| 14 | 5 | 70 |
| 16 | 4 | 64 |
Part 2:
Tyler should choose a length of 12 ft and a width of 6 ft to give his rabbit the most room.
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Part 1: Completing the Area Table
To find the area of a rectangle, we use the formula \( \text{Area} = \text{length} \times \text{width} \). Let's calculate the area for each row:
Row 1: Length = 8 ft, Width = 8 ft
Step 1: Apply the area formula
The formula for the area of a rectangle is \( A = l \times w \), where \( l \) is the length and \( w \) is the width.
Substitute \( l = 8 \) and \( w = 8 \) into the formula:
\( A = 8 \times 8 = 64 \) square feet.
Row 2: Length = 10 ft, Width = 7 ft
Step 1: Apply the area formula
Substitute \( l = 10 \) and \( w = 7 \) into \( A = l \times w \):
\( A = 10 \times 7 = 70 \) square feet.
Row 3: Length = 12 ft, Width = 6 ft
Step 1: Apply the area formula
Substitute \( l = 12 \) and \( w = 6 \) into \( A = l \times w \):
\( A = 12 \times 6 = 72 \) square feet.
Row 4: Length = 14 ft, Width = 5 ft
Step 1: Apply the area formula
Substitute \( l = 14 \) and \( w = 5 \) into \( A = l \times w \):
\( A = 14 \times 5 = 70 \) square feet.
Row 5: Length = 16 ft, Width = 4 ft
Step 1: Apply the area formula
Substitute \( l = 16 \) and \( w = 4 \) into \( A = l \times w \):
\( A = 16 \times 4 = 64 \) square feet.
The completed table is:
| length (ft) | width (ft) | area (sq ft) |
|---|---|---|
| 10 | 7 | 70 |
| 12 | 6 | 72 |
| 14 | 5 | 70 |
| 16 | 4 | 64 |
Part 2: Finding the Combination with the Most Room
To determine which length and width combination gives the most room (largest area), we compare the areas calculated in Part 1:
- For length = 8 ft, width = 8 ft: Area = 64 sq ft
- For length = 10 ft, width = 7 ft: Area = 70 sq ft
- For length = 12 ft, width = 6 ft: Area = 72 sq ft
- For length = 14 ft, width = 5 ft: Area = 70 sq ft
- For length = 16 ft, width = 4 ft: Area = 64 sq ft
Among these areas, 72 square feet is the largest, which corresponds to a length of 12 ft and a width of 6 ft.
Final Answers
Part 1:
| length (ft) | width (ft) | area (sq ft) |
|---|---|---|
| 10 | 7 | 70 |
| 12 | 6 | 72 |
| 14 | 5 | 70 |
| 16 | 4 | 64 |
Part 2:
Tyler should choose a length of 12 ft and a width of 6 ft to give his rabbit the most room.