QUESTION IMAGE
Question
type the correct answer in the box. use nconsider this expression.$sqrt{x^{4}-y^{2}}$when $x = 3$ and $y = -6$, the value of the
Step1: Substitute given values
Substitute $x=3$, $y=-6$ into $\sqrt{x^4 - y^2}$:
$\sqrt{3^4 - (-6)^2}$
Step2: Calculate exponents first
Compute $3^4$ and $(-6)^2$:
$\sqrt{81 - 36}$
Step3: Simplify inside the square root
Subtract the two values:
$\sqrt{45}$
Step4: Simplify the radical
Factor out perfect square:
$\sqrt{9 \times 5} = 3\sqrt{5}$
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$3\sqrt{5}$