QUESTION IMAGE
Question
unit: dimensional analysis
\one, two, and more step problems\
directions: use dimensional analysis to perform the following calculations. show all
work and include units.
- change 0.00765 kl into ml.
- a chemistry student’s height is measured at 68.5 inches. how tall is the student in cm?
- this same chemistry student has a weight of 155 lbs. what is the student’s weight in
grams? (16oz=1lb, 1 oz = 28.34 g)
- a homerun in a baseball game was measured at 450 feet. how many meters is this equal
to?
- mount everest is approximately 8,000 meters high. how many miles high is mount everest?
Response
Problem 1:
Step1: Recall unit conversion for volume. \(1\space kL = 1000\space L\) and \(1\space L = 1000\space mL\), so \(1\space kL = 1000\times1000 = 10^6\space mL\).
\(0.00765\space kL\times\frac{10^6\space mL}{1\space kL}\)
Step2: Multiply the numbers. \(0.00765\times10^6 = 7650\).
Step1: Recall the conversion factor: \(1\space inch = 2.54\space cm\).
\(68.5\space inches\times\frac{2.54\space cm}{1\space inch}\)
Step2: Multiply \(68.5\times2.54\). \(68.5\times2.54 = 174.0\) (approx, more accurately \(68.5\times2.54 = 173.99\approx174.0\)).
Step1: First convert pounds to ounces. \(1\space lb = 16\space oz\), so \(155\space lbs\times\frac{16\space oz}{1\space lb}\).
\(155\times16 = 2480\space oz\)
Step2: Then convert ounces to grams. \(1\space oz = 28.34\space g\), so \(2480\space oz\times\frac{28.34\space g}{1\space oz}\).
\(2480\times28.34 = 70283.2\)
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\(7650\space mL\)