Question

unit 5 practice test - graphing quadratics
use the given information to find the y coordinate of the vertex.

equation of the quadratic function	axis of symmetry is:	what is the vertex?
$y = x^2 + 10x + 13$	$x = -5$

Explanation:

Step1: Substitute $x=-5$ into the equation

Substitute $x=-5$ into $y = x^2 + 10x + 13$:
$y = (-5)^2 + 10(-5) + 13$

Step2: Calculate each term

Calculate each part of the expression:
$(-5)^2 = 25$, $10(-5) = -50$

Step3: Sum the terms to find $y$

Combine the calculated values:
$y = 25 - 50 + 13 = -12$

Answer:

$(-5, -12)$