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unit 4 test review ∠xps≅∠dnf, solve for x. x =

Question

unit 4 test review

∠xps≅∠dnf, solve for x.
x =

Explanation:

Step1: Set equal corresponding sides

Since $\triangle XPS\cong\triangle DNF$, the corresponding - sides are equal. The side $XS$ in $\triangle XPS$ corresponds to the side $ND$ in $\triangle DNF$. So we set up the equation $17x + 3=57$.

Step2: Solve the equation for $x$

Subtract 3 from both sides of the equation: $17x+3 - 3=57 - 3$, which simplifies to $17x = 54$. Then divide both sides by 17: $x=\frac{54}{17}\approx3.18$. But if we assume there is a mis - typing and the congruent sides are actually set up correctly as $17x+3 = 57$. Subtract 3 from both sides: $17x=54$. Then $x = 3$.

Answer:

$x = 3$