Question

unit test
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mr. shaw graphs the function $f(x) = -5x + 2$ for his class. the line contains the point $(-2, 12)$. what is the point-slope form of the equation of the line he graphed?
$circ$ $y - 12 = -5(x + 2)$
$circ$ $y - 12 = 2(x + 2)$
$circ$ $y + 12 = 2(x - 2)$
$circ$ $y + 12 = -5(x - 2)$

Explanation:

Step1: Identify slope and point

Slope $m=-5$, point $(x_1,y_1)=(-2,12)$

Step2: Use point-slope formula

Point-slope form: $y-y_1=m(x-x_1)$
Substitute values: $y-12=-5(x-(-2))$
Simplify the term inside parentheses: $y-12=-5(x+2)$

Answer:

$y - 12 = -5(x + 2)$