Question

unit test unit test review active solution preparation solubility of the solutes a rolf added 20 g of solute to 100 g of water and mixed the solution. the solute in solution a has a solubility of 37 g/100 g h₂o at 20°c. b rolf added 10 g of solute to 100 g of water and mixed the solution. the solute in solution b has a solubility of 10 g/100 g h₂o at 20°c. c rolf added 65 g of solute to 100 g of water, mixed the solution, and then heated the solution. the solute in solution c has a solubility of 32 g/100 g h₂o at 20°c. d rolf added 7 g of solute to 100 g of water, mixed the solution, and then heated the solution. the solute in solution d has a solubility of 4 g/100 g h₂o at 20°c. which solution is unsaturated? solution a solution b solution c

Explanation:

Step1: Recall the definition of unsaturated solution

An unsaturated solution has less solute dissolved than its solubility at a given temperature.

Step2: Analyze Solution A

The solubility is 37 g/100 g H₂O and 20 g of solute is added. Since 20g < 37g, it is unsaturated.

Step3: Analyze Solution B

The solubility is 10 g/100 g H₂O and 10 g of solute is added. It is a saturated solution (not unsaturated).

Step4: Analyze Solution C

The solubility is 32 g/100 g H₂O and 65 g of solute is added. Since 65g > 32g, it is supersaturated or has undissolved solute, not unsaturated.

Step5: Analyze Solution D

The solubility is 4 g/100 g H₂O and 7 g of solute is added. Since 7g > 4g, it is supersaturated or has undissolved solute, not unsaturated.

Answer:

Solution A