Question

use the accompanying radiation levels (in $\frac{w}{kg}$) for 50 different cell - phones. find the percentile $p_{30}$
$p_{30}=square\frac{w}{kg}$ (type an integer or decimal rounded to two decimal places as needed.)

Explanation:

Step1: Calculate the position

The formula to find the position of the $p$ -th percentile, $L$, in a data - set of size $n$ is $L=\frac{p}{100}\times n$. Here, $p = 30$ and $n=50$. So, $L=\frac{30}{100}\times50=15$.

Step2: Determine the percentile

Since $L = 15$ is an integer, the $30$th percentile $P_{30}$ is the average of the $15$th and $16$th ordered data - values. First, we order the data (which seems to be already ordered in the given list). The $15$th value is $0.95$ and the $16$th value is $0.96$. Then $P_{30}=\frac{0.95 + 0.96}{2}=\frac{1.91}{2}=0.96$.

Answer:

$0.96$