Question

use the activity series below to predict the products of each of the following reactions. you do not need to balance the equations.
li > k > ba > sr > ca > na > mg > al > mn > zn > cr > fe > cd >
co > ni > sn > pb > h > sb > bi > cu > ag > pd > hg > pt > au
$na_2co_3 + k \to ?$
no reaction
$k_2co_3 + na$
$nak + co_3$
$zncl_2 + cu \to ?$
no reaction
$cucl_2 + zn$
$cuzn + cl_2$

Explanation:

Step1: Analyze first reaction

Compare K and Na in activity series: $K > Na$. A more active metal displaces less active metal from its salt. So K displaces Na from $\text{Na}_2\text{CO}_3$, forming $\text{K}_2\text{CO}_3 + \text{Na}$.

Step2: Analyze second reaction

Compare Zn and Cu in activity series: $Zn > Cu$. Cu is less active, so it cannot displace Zn from $\text{ZnCl}_2$. No reaction occurs.

Answer:

1. $\text{Na}_2\text{CO}_3 + \text{K}

ightarrow \text{K}_2\text{CO}_3 + \text{Na}$

1. $\text{ZnCl}_2 + \text{Cu}

ightarrow \text{no reaction}$