Question

use ape - man to build the bohr models below.
sulfur
p =
n =
a =
p =
e =
m =
a =
n =
sodium
p =
n =
a =
p =
e =
m =
a =
n =
boron
p =
n =
a =
p =
e =
m =
a =
n =
neon
p =
n =
a =
p =
e =
m =
a =
n =

Explanation:

Step1: Recall APE-MAN rules

For neutral atoms: $P = E =$ atomic number; $A =$ mass number; $N = A - P$; $M$ (mass number) = $A$

Step2: Sulfur (atomic #16, mass #32)

$A = 32$, $P = 16$, $E = 16$
$M = 32$, $A = 32$, $N = 32 - 16 = 16$
Nucleus: $P=16$, $N=16$

Step3: Sodium (atomic #11, mass #23)

$A = 23$, $P = 11$, $E = 11$
$M = 23$, $A = 23$, $N = 23 - 11 = 12$
Nucleus: $P=11$, $N=12$

Step4: Boron (atomic #5, mass #11)

$A = 11$, $P = 5$, $E = 5$
$M = 11$, $A = 11$, $N = 11 - 5 = 6$
Nucleus: $P=5$, $N=6$

Step5: Neon (atomic #10, mass #20)

$A = 20$, $P = 10$, $E = 10$
$M = 20$, $A = 20$, $N = 20 - 10 = 10$
Nucleus: $P=10$, $N=10$

Answer:

Sulfur

Nucleus: $P=16$, $N=16$
$A=32$, $P=16$, $E=16$
$M=32$, $A=32$, $N=16$

Sodium

Nucleus: $P=11$, $N=12$
$A=23$, $P=11$, $E=11$
$M=23$, $A=23$, $N=12$

Boron

Nucleus: $P=5$, $N=6$
$A=11$, $P=5$, $E=5$
$M=11$, $A=11$, $N=6$

Neon

Nucleus: $P=10$, $N=10$
$A=20$, $P=10$, $E=10$
$M=20$, $A=20$, $N=10$