Question

use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table
drive-thru restaurant
\t\t\ta\tb\tc\td
order accurate\t317\t263\t239\t125
order not accurate\t31\t55\t33\t14
if one order is selected, find the probability of getting food that is not from restaurant a.

the probability of getting food that is not from restaurant a is
(round to three decimal places as needed )

Explanation:

Step1: Calculate total orders

First, we find the total number of orders by summing up all the values in the table.
For Restaurant A: \(317 + 31 = 348\)
For Restaurant B: \(263 + 55 = 318\)
For Restaurant C: \(239 + 33 = 272\)
For Restaurant D: \(125 + 14 = 139\)
Total orders \(= 348 + 318 + 272 + 139\)
\(= 348+318 = 666\); \(666 + 272 = 938\); \(938+139 = 1077\)

Step2: Calculate orders not from A

Orders from A are 348, so orders not from A \(= 1077 - 348 = 729\)

Step3: Calculate probability

Probability \(= \frac{\text{Orders not from A}}{\text{Total orders}}=\frac{729}{1077}\)
Simplify: \(\frac{729}{1077}\approx0.677\) (rounded to three decimal places)

Answer:

\(0.677\)