Question

use the data in the following table, which lists drive-thru order accuracy at popular fast food chains. assume that orders are randomly selected from those included in the table.
drive-thru restaurant
\t\t\ta\tb\tc\td
order accurate\t311\t265\t240\t135
order not accurate\t38\t50\t35\t16
if one order is selected, find the probability of getting food that is not from restaurant a.

the probability of getting food that is not from restaurant a is
(round to three decimal places as needed.)

Explanation:

Step1: Calculate total orders from all restaurants

First, we find the total number of orders by adding up all the accurate and not accurate orders for each restaurant.
For Restaurant A: \(311 + 38 = 349\)
For Restaurant B: \(265 + 50 = 315\)
For Restaurant C: \(240 + 35 = 275\)
For Restaurant D: \(135 + 16 = 151\)
Total orders \(= 349 + 315 + 275 + 151\)
\(= 349+315 = 664\); \(275 + 151 = 426\); \(664+426 = 1090\)

Step2: Calculate orders not from Restaurant A

Orders not from A = Total orders - Orders from A
Orders from A is 349, so orders not from A \(= 1090 - 349 = 741\)

Step3: Calculate the probability

Probability \(= \frac{\text{Orders not from A}}{\text{Total orders}} = \frac{741}{1090}\)
Calculating this: \(741\div1090 \approx 0.6798\approx 0.680\) (rounded to three decimal places)

Answer:

\(0.680\)