Question

use the diagrams below to answer questions 8 and 9. the atomic windows represent particles of the same gas occupying the same volume at the same temperature. the systems differ only in the number of gas particles per unit volume. 8. list the windows in order of decreasing density. 9. compare the density of the gas in window (a) to the density of the gas in window (b).

Explanation:

Step1: Recall density formula

Density $
ho=\frac{m}{V}$. Given same gas (so same molar - mass), same volume $V$, density is proportional to the number of particles $n$ (since $m = nM$, where $M$ is molar - mass).

Step2: Count particles in each window

In window (a), there are 5 particles. In window (b), there are 9 particles. In window (c), there are 8 particles.

Step3: Order by density

Since density is proportional to the number of particles per unit volume, the order of decreasing density is b > c > a.

Step4: Compare (a) and (b)

The number of particles in window (a) is 5 and in window (b) is 9. Since density is proportional to the number of particles per unit volume, the density of the gas in window (b) is greater than the density of the gas in window (a). The ratio of the density of gas in window (b) to window (a) is $\frac{
ho_b}{
ho_a}=\frac{n_b}{n_a}=\frac{9}{5}$.

Answer:

1. b > c > a
2. The density of the gas in window (b) is $\frac{9}{5}$ times the density of the gas in window (a).