Question

use the following information to answer the next question.
ca(oh)₂(aq) + al₂(so₄)₃(aq) → caso₄(s) + al(oh)₃(s)

1. determine how many moles of aluminum sulfate is reacted when 3.30 moles of calcium sulfate is produced.

□ 1.10
□ 4.95
□ 9.90
□ 3.30

Explanation:

Step1: Balance the chemical equation

$3Ca(OH)_2(aq)+Al_2(SO_4)_3(aq)
ightarrow3CaSO_4(s)+2Al(OH)_3(s)$

Step2: Determine mole - ratio

The mole - ratio of $Al_2(SO_4)_3$ to $CaSO_4$ from the balanced equation is $1:3$.

Step3: Calculate moles of $Al_2(SO_4)_3$

Let $n$ be the moles of $Al_2(SO_4)_3$. We know that $\frac{n}{n_{CaSO_4}}=\frac{1}{3}$, and $n_{CaSO_4} = 3.30$ moles. So $n=\frac{3.30}{3}=1.10$ moles.

Answer:

1.10