QUESTION IMAGE
Question
use the frequency distribution shown below to construct an expanded frequency distribution. high temperatures (°f)
class 20 - 30 31 - 41 42 - 52 53 - 63 64 - 74 75 - 85 86 - 96
frequency, f 17 44 68 69 76 68 23
complete the table below.
high temperatures (°f) (round to the nearest hundredth as needed.)
class frequency, f midpoint relative frequency cumulative frequency
20 - 30 17 25 0.05 17
31 - 41 44
Step1: Calculate the mid - point for the class 31 - 41
The mid - point formula for a class interval $a - b$ is $\frac{a + b}{2}$. For the class 31 - 41, the mid - point $x=\frac{31 + 41}{2}=\frac{72}{2}=36$.
Step2: Calculate the total frequency
The total frequency $n=17 + 44+68 + 69+76+68+23=365$.
Step3: Calculate the relative frequency for the class 31 - 41
The relative frequency formula is $\text{Relative Frequency}=\frac{\text{Frequency}}{\text{Total Frequency}}$. For the class 31 - 41 with frequency $f = 44$, the relative frequency $rf=\frac{44}{365}\approx0.12$.
Step4: Calculate the cumulative frequency for the class 31 - 41
The cumulative frequency is the sum of the frequencies of all classes up to and including the current class. For the class 31 - 41, the cumulative frequency $cf=17 + 44 = 61$.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
| Class | Frequency, f | Midpoint | Relative frequency | Cumulative frequency |
|---|---|---|---|---|
| 31 - 41 | 44 | 36 | 0.12 | 61 |