Question

use the frequency table to compute the following. probability of voting for seriously though: p(a)= probability of voting for seeing is not believing: p(b)= probability of voting for seriously though and voting for seeing is not believing: p(a and b)= probability of voting for seriously though or voting for seeing is not believing: p(a or b)= event a: voting for seriously though event b: voting for seeing is not believing

Explanation:

Step1: Calculate P(A)

The total number of voters is 165. The number of voters who voted for Seriously Though is 52. So, $P(A)=\frac{52}{165}$.

Step2: Calculate P(B)

The number of voters who voted for Seeing is Not Believing is 113 (56 + 44+ 13). So, $P(B)=\frac{113}{165}$.

Step3: Calculate P(A and B)

The number of voters who voted for both Seriously Though and Seeing is Not Believing is 0. So, $P(A\ and\ B) = 0$.

Step4: Calculate P(A or B)

Using the formula $P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$, we substitute the values: $P(A\ or\ B)=\frac{52}{165}+\frac{113}{165}- 0=\frac{52 + 113}{165}=\frac{165}{165}=1$.

Answer:

$P(A)=\frac{52}{165}$
$P(B)=\frac{113}{165}$
$P(A\ and\ B)=0$
$P(A\ or\ B)=1$