Question

use the graph to complete each statement about the situation.
the maximum profit the florist will earn from selling celebration bouquets is $
the florist will break - even after one - dollar decreases.
the interval of the number of one - dollar decreases for which the florist makes a profit from celebration bouquets is ( , )

Explanation:

Step1: Identify max profit (vertex)

The highest point (vertex) of the parabola is at $y=600$.

Step2: Find break-even points (x-intercepts)

The parabola crosses the x-axis at $x=-12$ and $x=20$. Since the number of decreases can't be negative, the valid break-even point is 20 one-dollar decreases.

Step3: Determine profit interval

Profit occurs where $y>0$, between the two x-intercepts: $-12$ and $20$. Since negative decreases don't make practical sense, the interval uses the valid range of positive/non-negative decreases, but mathematically the interval is $(-12, 20)$.

Answer:

The maximum profit the florist will earn from selling celebration bouquets is $\boldsymbol{600}$
The florist will break-even after $\boldsymbol{20}$ one-dollar decreases.
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is $\boldsymbol{(-12, 20)}$