Question

use the image to answer the question. letitia tells her son, evan, that he may have one piece of candy with his lunch. calculate the probability of choosing each color of candy. yellow: green: purple: pink:

Explanation:

1. First, count the total number of candies:

• By counting the candies in the bag, we find there are 10 candies in total.

1. Then, count the number of each - color candies and calculate the probabilities:

• Yellow candies:
• There are 3 yellow candies. The probability formula is \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). So the probability of choosing a yellow candy is \(P_{yellow}=\frac{3}{10}\).
• Green candies:
• There are 2 green candies. So the probability of choosing a green candy is \(P_{green}=\frac{2}{10}=\frac{1}{5}\).
• Purple candies:
• There is 1 purple candy. So the probability of choosing a purple candy is \(P_{purple}=\frac{1}{10}\).
• Pink candies:
• There are 4 pink candies. So the probability of choosing a pink candy is \(P_{pink}=\frac{4}{10}=\frac{2}{5}\).

Step1: Count total candies

Counted 10 candies in bag.

Step2: Calculate yellow - candy probability

\(P_{yellow}=\frac{3}{10}\)

Step3: Calculate green - candy probability

\(P_{green}=\frac{2}{10}=\frac{1}{5}\)

Step4: Calculate purple - candy probability

\(P_{purple}=\frac{1}{10}\)

Step5: Calculate pink - candy probability

\(P_{pink}=\frac{4}{10}=\frac{2}{5}\)

Answer:

Yellow: \(\frac{3}{10}\), Green: \(\frac{1}{5}\), Purple: \(\frac{1}{10}\), Pink: \(\frac{2}{5}\)