Question

1. use the pythagorean theorem to find the distance between (10, 0) and (-9, -3). round to the nearest tenth.

Explanation:

Step1: Find horizontal distance

Let $(x_1,y_1)=(10,0)$ and $(x_2,y_2)=(-9,-3)$. The horizontal distance $a=\vert x_1 - x_2\vert=\vert10-(-9)\vert = 19$.

Step2: Find vertical distance

The vertical distance $b=\vert y_1 - y_2\vert=\vert0 - (-3)\vert=3$.

Step3: Apply Pythagorean Theorem

By the Pythagorean Theorem $d=\sqrt{a^{2}+b^{2}}$, where $d$ is the distance between the two points. Substitute $a = 19$ and $b = 3$ into the formula: $d=\sqrt{19^{2}+3^{2}}=\sqrt{361 + 9}=\sqrt{370}\approx19.2$.

Answer:

$19.2$