Question

7 use the segment addition postulate to solve for x. a x + 5 b 2x + 10 c 33 a 6 b 5 c 8 d 7

Explanation:

Step1: Apply segment - addition postulate

$(x + 5)+(2x + 10)=33$

Step2: Combine like - terms

$x+2x+5 + 10=33$
$3x+15 = 33$

Step3: Isolate the variable term

Subtract 15 from both sides: $3x+15−15=33−15$
$3x=18$

Step4: Solve for x

Divide both sides by 3: $\frac{3x}{3}=\frac{18}{3}$
$x = 6$

Answer:

A. 6