Question

using the equation c₁₂h₂₂o₁₁ + 12o₂ -> 12co₂ + 11h₂o if 156 l of o₂ at stp are consumed how many moles of sucrose are required? 0.580 mol 291 mol 6.96 mol 3.50 × 10³ mol

Explanation:

Step1: Find moles of \( O_2 \) at STP

At STP, 1 mole of any gas occupies 22.4 L. So moles of \( O_2 \), \( n_{O_2}=\frac{V}{22.4\ L/mol}=\frac{156\ L}{22.4\ L/mol}\approx6.964\ mol \)

Step2: Use stoichiometry from the equation

The balanced equation is \( C_{12}H_{22}O_{11}+12O_2
ightarrow12CO_2 + 11H_2O \). The mole ratio of \( C_{12}H_{22}O_{11} \) to \( O_2 \) is \( 1:12 \). Let moles of sucrose be \( n \). Then \( \frac{n}{n_{O_2}}=\frac{1}{12} \), so \( n=\frac{n_{O_2}}{12}=\frac{6.964\ mol}{12}\approx0.580\ mol \)

Answer:

0.580 mol